C x O(n) < O(n²) is NOT always true, there is a point in n where it reverses the condition.
When C is large and n is small, then C x O(n) > O(n²).
However, C is always constant, hence when n scales to a large number, C x O(n) < O(n²).
Therefore, when n is large, O(n) is always better than O(n²).