get a count of each value from every column in a table SQL Server

Question

So I looked this up and this question is very similar but it\'s missing a key piece: SQL Server count number of distinct values in each column of a table

So in that

Answer 1

This version makes a good snippet:

DECLARE @sql NVARCHAR(MAX) = N'';

SELECT @sql += 'SELECT ''' + t.name + ''', ''' + c.name + ''', ' + c.name + ', COUNT(' + c.name + ') AS C FROM ' + QUOTENAME(s.name) + '.' + QUOTENAME(t.name) + ' GROUP BY ' + c.name + ';' + CHAR(13)
    FROM sys.tables AS t
    INNER join sys.columns c on t.object_id = c.object_id
    INNER JOIN sys.schemas AS s ON t.[schema_id] = s.[schema_id] 
    WHERE s.name LIKE 'stage' AND t.name LIKE 'table' AND c.name LIKE '%whatever%';

--PRINT @sql;
EXEC sp_executesql @sql