get a count of each value from every column in a table SQL Server

Question

So I looked this up and this question is very similar but it\'s missing a key piece: SQL Server count number of distinct values in each column of a table

So in that

Answer 1

thought i would take a stab at this whilst waiting for a backup to restore

hope this does what you require

create Table #Temp 
(tableName varchar(100),
columnName varchar(100),
value varchar(1000),
distinctItems int)

Declare @tabName as varchar(100)
Declare @colName as varchar(100)
Declare @tabid as int

Declare cursorTables Cursor
for 
select t.object_id , t.name , c.name from sys.tables t inner join sys.columns c on     t.object_id = c.object_id

open cursorTables 
Fetch Next from cursorTables into 
@tabid,@tabName,@colName


while @@Fetch_Status = 0 
Begin

declare @query as nVarchar(1000)
set @query  = 'Insert into #Temp SELECT    ''' + @tabName + '''  , '''+ @colName +''', '     + @colName + ',  COUNT([' + @colName +']) AS Expr1 FROM          [' + @tabName+ '] group by     [' + @colName + ']'
print @query
exec sp_executesql @query

Fetch Next from cursorTables into 
@tabid,@tabName,@colName


End 

Close cursorTables
Deallocate cursorTables

select * from #temp

drop table #temp

produces some not very useful results on PK values and i suspect it would not work on columns greater than varchar(1000) but works on a fe of my dbs