I have the following XPath:
//div[contains(@id, \'box\')]/div/h4/small/a[contains(@href, \'google\')]/@href
When I try out this XPath in XP
In Selenium RC: it needs to mention xpath as "xpath=//div[contains(@id, 'box')]/div/h4/small/a[contains(@href, 'google')]/@href". So in your case, the code is as below:
selenium.getAttribute("xpath=//div[contains(@id, 'box')]/div/h4/small/a[contains(@href, 'google')]/@href");
In Selenium WebDriver: the code is as below:
driver.findElement(By.xpath("//div[contains(@id, 'box')]/div/h4/small/a[contains(@href, 'google')]/@href")).getAttribute("The name of the attribute");