Split string on a backslash (“\”) delimiter in awk?

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花落未央
花落未央 2021-01-14 17:56

I am trying to split the string in a file based on some delimiter.But I am not able to achieve it correctly... Here is my code below.

awk \'var=split($2,arr,         


        
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  •  夕颜
    夕颜 (楼主)
    2021-01-14 18:43

    Sample data and output is my best guess at your requirement

     echo '1:2\\a\\b:3' | awk -F: '{ 
         n=split($2,arr,"\\")
         # print "#dbg:n=" n
         var=arr[3]
         print var
         }'
    

    output

    b
    

    Recall that split returns the number of fields that it found to split. You can uncomment the debug line and you'll see the value 3 returned.

    Note also that for my test, I had to use 2 '\' chars for 1 to be processed. I don't think you'll need that in a file, but if this doesn't work with a file, then try adding extra '\' as needed to your data. I tried several variations on how to use '\', and this seems the most straightforward. Others are welcome to comment!

    I hope this helps.

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