date( ) returns 1970-01-01

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醉梦人生
醉梦人生 2021-01-14 16:37

I am using a jquery datepicker with the following format mm/dd/yyyy but I need it to be yyyy-mm-dd for the sql db so I am using this.

   $date  = date(\"Y-m-         


        
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  •  生来不讨喜
    2021-01-14 16:58

    When you get 1970-01-01 back from date() it means that the timestamp is incorrect. That date is the UNIX epoch.

    When it comes to Javascript (in this case a datepicker) you should always make sure that what you get is, in fact, what you expect it to be. Simply passing it through strtotime() will cause problems like the one you have here.

    One good way to handle dates is using the datetime extension. It has a static method, DateTime::createFromFormat, that will let you parse any date using any format:

    // The value from the datepicker
    $dpValue = '12/30/2013';
    
    // Parse a date using a user-defined format
    $date = DateTime::createFromFormat('d/m/Y', $dpValue);
    
    // If the above returns false then the date
    // is not formatted correctly
    if ($date === false) {
        header('HTTP/1.0 400 Bad Request');
        die('Invalid date from datepicker!')
    }
    
    // Using the parsed date we can create a
    // new one with a formatting of out choosing
    $forSQL = $date->format('Y-m-d');
    
    // ...
    

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