using list operator “in” with floating point values

Question

I have a list with floats, each number with 3 decimals (eg. 474.259). If I verify the number in the list like this:

if 474.259 in list_sample:
    print \"so         


        

Answer 1

You can use numpy.isclose() instead of Python's in.

import numpy as np
other_list = np.array([474.251001, 123.456])
number = other_list[0]
number = round(number, 3)
if number == 474.251:
    print "number == 474.251"
if number in other_list:
    print "number in other_list"
if any(np.isclose(number, other_list, rtol=1e-7)):
    print 'any(np.isclose(number, other_list, rtol=1e-7))'

Output:

number == 474.251
any(np.isclose(number, other_list, rtol=1e-7))