Scope of new memory in C++

Question

When I try to do the following I get an error saying I\'m trying to read or write to protected memory.

void func1(int * ptr) {
    int *ptr_b = new int[5];
          


        

Answer 1

Change your signature to:

void func1(int *& ptr)

You're passing the pointer by value, so the outside ptr doesn't get changed. So it's like doing

int main() {  // <--- main returns int
    int *ptr_a;
    delete [] ptr_a;
}

which is illegal, since ptr_a is not initialized.