Scope of new memory in C++

Question

When I try to do the following I get an error saying I\'m trying to read or write to protected memory.

void func1(int * ptr) {
    int *ptr_b = new int[5];
          


        

Answer 1

No. You're making a common beginner mistake. You're not remembering that pointers are just variables that are passed by value unless you ask for a reference or pointer to them. Change the signature of your function to void func1(int *& ptr)