Print last matching line?

Question

Using awk, I would like to print the last matching line of a file. I would like only the matching line itself, not any range of lines. I can use a command like

Answer 1

sed solution:

sed -n '/foo/h;$!b;g;p' bar.txt

Place the matching regex in hold buffer and branch out. Keep doing this until end of file. When the end of file is reached, grab the line from hold space and place it on pattern space. Print pattern space.