getting a string length that contains unicode character exceeding 0xffff

Question

I’m using this character, double sharp \'

Answer 1

To sumarize my comments:

That's just the lenght of that string.

Some chars involve other chars as well, even if it looks like a single character. "̉mủt̉ả̉̉̉t̉ẻd̉W̉ỏ̉r̉̉d̉̉".length == 24

From this (great) blog post, they have a function that will return correct length:

function fancyCount(str){
  const joiner = "\u{200D}";
  const split = str.split(joiner);
  let count = 0;
    
  for(const s of split){
    //removing the variation selectors
    const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
    count += num;
  }
    
  //assuming the joiners are used appropriately
  return count / split.length;
}

console.log(fancyCount("F

             

                                                        
            

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