Get last parameter on shell script [duplicate]

Answer 1

The script below shows how you can get the first and last arguments passed to a script:

numArgs="$#"
echo "Number of args: $numArgs"

firstArg="$1"
echo "First arg: $firstArg"

lastArg="${!#}"
echo "Last arg: $lastArg"

Output:

$ ./myshell_script.sh a b c d e f
Number of args: 6
First arg: a
Last arg: f