Java: Sort a list of words by length, then by alphabetical order

Question

I am told to have a list of words sorted by length, and those that have the same length are sorted by alphabetical order. This is what I have for the method that does that s

Answer 1

You can do that using simple List. Try following code.

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;


/**
 *
 * @author Masudul Haque
 */
public class LengthSort {
    public static void main(String[] args) {
        List list=new ArrayList<>();
        list.add("cowa");
        list.add("cow");
        list.add("aow");
        Collections.sort(list, new Comparator() {

            @Override
            public int compare(String o1, String o2) {
                if(o1.length()>o2.length()){
                    return 1;
                }else{
                    return o1.compareTo(o2);
                }
            }
        });

        System.out.println(list);
    }
}