I have a question on pattern matching:
Is it possible to somehow match a (string ++ [char] ++ anotherstring)?
I have tried something like:
f
For completeness' sake, one could make gratuitous use of GHC's ViewPatterns
extension, and rewrite Daniel Fischer's example as something like:
{-# LANGUAGE ViewPatterns #-}
f (break (== ';') -> (s, _:r)) = s ++ r
f _ = error "No semicolon found"
This is of course a purely cosmetic change, but if you prefer the usual "group of equations" syntax instead of case
expressions, there it is.
N.B. -- I don't have GHC at hand right now so I haven't actually tested the above.