How to dynamically modify a function's local namespace?

Question

NB: This question assumes Python 2.7.3.

I\'m looking for a sane approach to dynamically modify a function\'s local namespace, preferably in a way that adds the lea

Answer 1

Not sure if it is possible with an external function only. I've created a snippet:

def get_module_prefix(mod, localsDict):
    for name, value in localsDict.iteritems():
        if value == mod:
            return name
    raise Exception("Not found")

def get_new_locals(mod, localsDict):
    modulePrefix = get_module_prefix(mod, localsDict)
    stmts = []
    for name in dir(mod):
        if name.startswith('_'):
            continue
        if name not in localsDict:
            continue
        stmts.append("%s = %s.%s" % (name, modulePrefix, name))
    return "\n".join(stmts)

def func(someName):
    from some.dotted.prefix import some.dotted.name
    #here we update locals
    exec(get_new_locals(some.dotted.name, "some.dotted.name", locals()))
    print locals()
    print someName # value taken from aModule instead of parameter value


func(5)

where:

• get_module_prefix is used to find the name under which the module is imported,
• get_new_locals returns assignment statements which can be used to update locals,

The actual update of locals is performed in line exec(get_new_locals(some.dotted.name, locals())) where we simply execute assignment statements in which we assign values from the module to local variables.

I am not sure if it is what you actually ment.