Consider the following line of code:
The output of that is 3, which is the expec
In this code:
echo '10 - 7 = '.$x-$y;
The concatenation takes precedence, so what you're left with is this:
echo '10 - 7 = 10'-$y;
Because this is trying to perform integer subtraction with a string, the string is converted to an integer first, so you're left with something like this:
echo (int)'10 - 7 = 10'-$y;
The integer value of that string is 10
, so the resulting arithmetic looks like this:
echo 10-$y;
Because $y
is 7
, and 10 - 7 = 3
, the result being echoed is 3
.