Print file in particular order in bash

Question

I have file with content:

file.txt:

Iteration 1
RAM: +456ms
Cache: +142ms (total +417ms)

Iteration 2
Spec: +152ms
Cache: +149ms (total +413ms)

Iter         


        

Answer 1

Simply:

#!/bin/bash
for i in RAM Cache Spec Searchms; do
    echo "$i `cat file.txt  | grep $i | grep -Eo '[0-9]{1,9}' | tr '\n' ' '`" >> out.txt
done

You can change the order in line 2 ( for loop )

Output:

$ cat out.txt 
RAM 456 184 149 
Cache 142 417 149 413 
Spec 152 172 
Searchms 131 385 188