size of a structure containing bit fields [duplicate]

Answer 1

I took another look at this and here's what I found.

1. From the C book, "Almost everything about fields is implementation-dependant."
2. On my machine:

 struct B {
    unsigned c: 8;
    unsigned b: 1;
}b;
printf("%lu\n", sizeof(b));

print 4 which is a short;

You were mixing bit fields with regular struct elements.

BTW, a bit fields is defined as: "a set of adjacent bits within a sindle implementation-defined storage unit" So, I'm not even sure that the ':8' does what you want. That would seem to not be in the spirit of bit fields (as it's not a bit any more)