How to count consecutive duplicates in a table?

Question

I have below question:
Want to find the consecutive duplicates

SLNO   NAME     PG   
1       A1      NO                   
2       A2      YES                    


        

Answer 1

with test as (
select 1 slno,'A1' name ,'NO' pg from dual union all 
select 2,'A2','YES' from dual union all
select 3,'A3','NO' from dual union all
select 4,'A4','YES' from dual union all
select 6,'A5','YES' from dual union all
select 7,'A6','YES' from dual union all
select 8,'A7','YES' from dual union all
select 9,'A8','YES' from dual union all
select 10,'A9','YES' from dual union all
select 11,'A10','NO' from dual union all
select 12,'A11','YES' from dual union all
select 13,'A12','NO' from dual union all
select 14,'A14','NO' from dual),
consecutive as (select row_number() over(order by slno) rr, x.* 
              from test x)
select x.* from Consecutive x
  left join Consecutive y on x.rr = y.rr+1 and x.pg = y.pg
  where y.rr is not null
  order by x.slno 

And you can control output with condition in where.

where y.rr is not null query returns duplicates

where y.rr is null query returns "distinct" values.