Cannot implement two interfaces that have the same method name

Question

This doesn\'t work:

interface TestInterface
{
    public function testMethod();
}

interface TestInterface2
{
    public function testMethod();
}

class Test         


        

Answer 1

It makes no sense to implement two interfaces containing methods with the same signatures.

The compiler cannot know if the methods actually have the same purpose - if not, it would mean that at least one of the interfaces cannot be implemented by your class.

Example:

interface IProgram { function execute($what); /* executes the given program */ }
interface ISQLQuery { function execute($what); /* executes the given sql query */ }

class PureAwesomeness implements IProgram, ISQLQuery {
    public function execute($what) { /* execute something.. but what?! */ }
}

So as you see, it's impossible to implement the method for both interfaces - and it'd also be impossible to call the method which actually implements the method from a given interface.