The order of cout messages is not as expected

Question

I am confused with the output of below code when I execute it.

Code:

int add(int a, int b)
{
    cout<<\"inside int add function\"<

        

Answer 1

This line in you code:

cout<

will be translated by the compiler into:

operator<<(operator<<(operator<<(cout,add(10.0f,20.0f)),endl),add(20,50));

As the order of evaluation of function parameters is not mandated by the standard, it just happens that add(20,50) is evaluated before operator<<(operator<<(cout,add(10.0f,20.0f)),endl).