Sliding window iterator using rolling in pandas

Question

If it\'s single row, I can get the iterator as following

import pandas as pd
import numpy as np

a = np.zeros((100,40))
X = pd.DataFrame(a)

for index, row i         


        

Answer 1

That's not how rolling works. It "provides rolling transformations" (from the docs).

You can loop and use pandas indexing?

for i in range((X.shape[0] + 9) // 10):
    X_subset = X.iloc[i * 10: (i + 1) * 10])