Android - SeparatedListAdapter - How to get accurate item position on onClick?

Question

I\'m using Sharkey\'s SeparatedListAdapter class in order to have a ListView that is separated by sections.

The class works great, but the problem I\'m having is in

Answer 1

For anyone else I too recently ran into this problem and ended up here, I solved by:

First altering the Map to take an 'id'

public Map createItem(String title, String caption, String id) { 
  Map item = new HashMap(); 
  item.put(ITEM_TITLE, title); 
  item.put(ITEM_CAPTION, caption); 
  item.put("id", id); // Add a unique id to retrieve later
  return item;}

Second when adding a section make sure to include an id:

 List> GeneralSection = new LinkedList>(); 
          GeneralSection.add(createItem(FirstName[GeneralInt] + " " + LastName[GeneralInt], Whatever[GeneralInt], UniqueId[GeneralInt]));   
//Unique id could be populated anyway you like, database index 1,2,3,4.. for example like above question.
          adapter.addSection("GeneralSection ", new SimpleAdapter(getActivity(), GeneralSection , R.layout.list_complex, 
            new String[] { ITEM_TITLE, ITEM_CAPTION }, new int[] { R.id.list_complex_title, R.id.list_complex_caption }));

Finally Use a Map in ItemClickListener to retrieve 'id' of the correct position:

  @Override
        public void onItemClick(AdapterView arg0,  View v, int position, long arg3) {
            // TODO Auto-generated method stub

            Map map = (Map) arg0.getItemAtPosition(position);
            String UniqueId = map.get("id");
            Log.i("Your Unique Id is", UniqueId); 
//Can then use Uniqueid for whatever purpose
//or any other mapped data for that matter..eg..String FirstName = map.get("ITEM_TITLE");


    }

Hope this helps someone.