Is `sscanf` guaranteed not to change arguments that it doesn't find?

Question

I have a case where I\'m not sure if I\'ll get enough input for sscanf. Can I safely assume that sscanf won\'t mess with any argument that it doesn

Answer 1

From http://pubs.opengroup.org/onlinepubs/009695399/functions/scanf.html:

... If the format is exhausted while arguments remain, the excess arguments shall be evaluated but otherwise ignored.

Edit: As Kerrek correctly noticed, the above statement does not apply here. It is about sscanf("1", "%d", &a, &b, &c), and not about sscanf("1", "%d %d %d", &a, &b, &c) as in the question.