Convert Dictionary to Numpy array

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予麋鹿
予麋鹿 2021-01-13 05:47

I am trying to convert the dictionary

{0: {0: 173, 1: 342, 2: 666, 3: 506, 4: 94},
 1: {0: 13, 1: 2171, 2: 1915, 3: 3075, 4: 630},
 2: {0: 0, 1: 265, 2: 503         


        
1条回答
  •  说谎
    说谎 (楼主)
    2021-01-13 06:30

    A Python-level loop is unavoidable here, so you can use a list comprehension:

    res = np.array([list(item.values()) for item in d.values()])
    
    # array([[ 173,  342,  666,  506,   94],
    #        [  13, 2171, 1915, 3075,  630],
    #        [   0,  265, 5036,  508,   11],
    #        [   0, 3229, 2388, 3649,  193],
    #        [   3,  151,  591, 1629,  410]])
    

    As per @FHTMitchell's comment, this assumes your dictionary items (inner and outer) are ordered appropriately. Dictionaries are insertion ordered in 3.6 as a CPython implementation detail, and officially in 3.7+.

    One way to define an order for inner and outer dictionaries is via operator.itemgetter:

    getter = itemgetter(*range(5))
    res = np.array([getter(item) for item in getter(d)])
    

    Such a solution does not depend on the order of your input dictionary.

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