The most efficient way to reverse a number

Question

I am looking for an efficient algorithm to reverse a number, e.g.

Input: 3456789

Output: 9876543

In C++ there are p

Answer 1

This is the easiest one:

#include
using namespace std;

int main()
{
int number, reversed=0;
cout<<"Input a number to Reverse: ";
cin>>number;
    while(number!=0)
  {
    reversed= reversed*10;
    reversed=reversed+number%10;
    number=number/10;
  }
cout<<"Reversed number is: "<