Filenames with wildcards in variables

Question

#!/bin/bash
outbound=/home/user/outbound/
putfile=DATA_FILE_PUT_*.CSV
cd $outbound
filecnt=0
for file in $putfile; do let filecnt=filecnt+1; done
echo \"Filecount: \         


        

Answer 1

You could test if file exists first

for file in $putfile; do
  if [ -f "$file" ] ; then
    let filecnt=filecnt+1
  fi
done

Or look for your files with find

for file in $(find . -type f -name="$putfile"); do
  let filecnt=filecnt+1
done

or simply (fixed)

filecnt=$(find . -type f -name "$putfile" | wc -l); echo $filecnt