Why isn't the result of this cast an lvalue?

Question

I need some advice with this strange behavior – lets have this code:

int ** p;

This compiles without any trouble:

p++;
         


        

Answer 1

Why isn't the result of this cast an lvalue?

I draw your attention to section 6.5.4 of the C99 specification, line 4, footnote 86, which states:

A cast does not yield an lvalue.

You have a cast.

The result is not an lvalue.

The ++ operator requires an lvalue.

Therefore your program is an error.