How to iterate over the results of a generator function

Question

Is there a better way to iterate over the results of a generator, my for loop is ugly:

for(let job = readyJob.next(); !job.done; job = readyJob.next()){ } 
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Answer 1

Yes, if your environment already supports for...of:

for (var job of readyJob) {
  // ...
}

If not, have seen this a couple of times:

var next;
while (!(next = readyJob.next()).done) {
   var job = next.value;
   // ...
}