So malloc doesn't invoke any syscall?

Question

Related code:

  write(-1, \"test\", sizeof(\"test\"));
  void * p = malloc(1024);
  void * p2 = malloc(510);
  write(-1, \"hi\", sizeof(\"hi\"));
         


        

Answer 1

What do you think brk is? malloc absolutely is invoking a syscall in this example, the syscall just isn't "malloc".