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JAXB Unmarshalling @XmlAnyElement

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一个人的身影
一个人的身影 2021-01-12 18:07

I have created three JAXB class : Home , Person , Animal . Java Class Home have variable List any that may contain Person and/or Ani
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  • 再見小時候
    再見小時候 (楼主)
    2021-01-12 18:25

    You need to add @XmlRootElement on the classes you want to appear as instances in the field/property you have annotated with @XmlAnyElement(lax=true).

    Java Model

    Home

    import java.util.List;
import javax.xml.bind.annotation.*;

@XmlAccessorType(XmlAccessType.FIELD)
public class Home {
    @XmlAnyElement(lax = true)
    protected List any;

    //setter getter also implemented
}



    Person 
    


    import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="Person")
public class Person {

    


    }
    


    Animal
    


    import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="Animal")
public class Animal {

}

    


    Demo Code
    


    input.xml
    


    

    
    
    


    


    Demo
    


    import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;

public class Demo {

    public static void main(String[] args) throws JAXBException {
        JAXBContext jc = JAXBContext.newInstance(Home.class, Person.class, Animal.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        StreamSource xml = new StreamSource("src/forum20329510/input.xml");
        Home home = unmarshaller.unmarshal(xml, Home.class).getValue();

        for(Object object : home.any) {
            System.out.println(object.getClass());
        }
    }

}

    


    Output
    


    class forum20329510.Person
class forum20329510.Animal
class forum20329510.Person

    


    For More Information
    


      

    • http://blog.bdoughan.com/2012/12/jaxbs-xmlanyelementlaxtrue-explained.html
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