How to remove scheme from url in Python?

Question

I am working with an application that returns urls, written with Flask. I want the URL displayed to the user to be as clean as possible so I want t

Answer 1

If you are using these programmatically rather than using a replace, I suggest having urlparse recreate the url without a scheme.

The ParseResult object is a tuple. So you can create another removing the fields you don't want.

# py2/3 compatibility
try:
    from urllib.parse import urlparse, ParseResult
except ImportError:
    from urlparse import urlparse, ParseResult


def strip_scheme(url):
    parsed_result = urlparse(url)
    return ParseResult('', *parsed_result[1:]).geturl()

You can remove any component of the parsedresult by simply replacing the input with an empty string.

It's important to note there is a functional difference between this answer and @Lukas Graf's answer. The most likely functional difference is that the '//' component of a url isn't technically the scheme, so this answer will preserve it, whereas it will remain here.

>>> Lukas_strip_scheme('https://yoman/hi?whatup')
'yoman/hi?whatup'
>>> strip_scheme('https://yoman/hi?whatup')
'//yoman/hi?whatup'