NSWidgetExtensionContext openURL Swift

Question

I have been attempting to implement a button to open my iOS app from its widget. I realize this issue has been beaten to death on the forums but I cannot find explanation wi

Answer 1

Also you should check if you are using any not allowed character for your url scheme. Maybe it is not your case but I was using this and it was wrong:

my_AppName

instead this finally worked :)

myAppName

as said here, the scheme must begin with alphanumeric character and it can contain only alphanumeric characters, +, - and .