I test the following code:
for i in range(3):
for i in range(3,5):
print \"inner i: %d\"%(i)
print \"outer i: %d\"%(i)
and
It's the same i
, Python doesn't have block scope. At the beginning of each for-loop iteration, you assign the the next value in the iterator to i
. Python for-loops aren't like C/Java for-loops, they are foreach loops. The continue until the iterator is exhausted (or you break
out somehow). A for-loop is equivalent to the following while-loop:
iterator = iter(my_iterable)
while True:
try:
x = next(iterator)
except StopIteration:
break
do_stuff(x)
So, your nested loop is the equivalent of this:
it1 = iter(range(3))
while True:
try:
i = next(it1)
except StopIteration:
break
it2 = iter(range(3, 5))
while True:
try:
i = next(it2)
except StopIteration:
break
print "inner i: %d"%(i)
print "outer i after: %d"%(i)
Note, a C/Java for-loop, e.g.:
for (int i = 0; i < stop; i++){
do_stuff(i);
}
Would be in Python:
i = 0
while i < stop:
do_stuff(i)
i += 1
In other words, the classic-for-loop depends on i
, that is, the termination condition depends on the value of i
. But in a for-each loop, the termination condition depends on the iterator. And it doesn't matter what you do to the variable inside the body, at the beginning of each iteration, it is assigned the next value of the iterator.