Modifying a parameter pass to a script (Bash)

Question

I have been looking on Google for quite a while now and can\'t find anything that is matching what I need/want to do.

My objective is to write a script that takes tw

Answer 1

To set the positional parameters $1, $2, ..., use the set command:

set foo bar baz
echo "$*"   # ==> foo bar baz
echo $1     # ==> foo

set abc def
echo "$*"   # ==> abc def

If you want to modify one positional parameter without losing the others, first store them in an array:

set foo bar baz
args=( "$@" )
args[1]="BAR"
set "${args[@]}"
echo "$*"   # ==> foo BAR baz