How to pass a function as a function parameter in Python

Question

This is what I currently have and it works fine:

def iterate(seed, num):
    x = seed
    orbit = [x]
    for i in ran         


        

Answer 1

Just pass the function as a parameter. For instance:

def iterate(seed, num, func=lambda x: 2*x*(1-x)):
    x = seed
    orbit = [x]
    for i in range(num):
        x = func(x)
        orbit.append(x)
    return orbit

You can then either use it as you currently do or pass a function (that takes a single argument) eg:

iterate(3, 12, lambda x: x**2-3)

You can also pass existing (non lambda functions) in the same way:

def newFunc(x):
    return x**2 - 3

iterate(3, 12, newFunc)