Python map function, passing by reference/value?

Question

I have a question about the map function in Python.

From what I understand, the function does not mutate the list it\'s operating on, but rather create

Answer 1

You misunderstand how references work in Python. Here, all names are references, there are no "values". Names are bound to objects. But = doesn't modify the object that's pointed to by the name — it rebinds the name to a different object:

x = 42
y = x
# now:
# 'is' is a identity operator — it checks whether two names point to the
# exact same object
print x is y # => True
print x, y   # 42 42
y = 69
# now y has been rebound, but that does not change the '42' object, nor rebinds x
print x is y # => False
print x, y   # 42 69

To modify the object itself, it needs to be mutable — i.e. expose members that mutate it or have a modifiable dict. The same thing as above happens when you rebind p — it doesn't touch points at all, it simply modifies the meaning of local p name.

If you want to simulate C++-like references, you need to encapsulate the object into a mutable container, e.g. a list.

reflect([points], 'X')

# inside reflect:
p[0] = ...

But you shouldn't, at least in this case — you should just return the new object instead.

points = reflect(points, 'X')

# inside reflect, instead of p = ...
return map(func, p)

Well, now that I think about it, you can also do

p[:] = map(func, p)

But again, returning new object is usually better.