template specialization of template class

Question

I want to specialize following member function:

class foo {
    template
    T get() const;
};

To other class bar

Answer 1

You can't partially specialize function templates, sorry but those are the rules. You can do something like:

class foo {
   ...
};


template
struct getter {
  static T get(const foo& some_foo);
};

template
struct getter< std::pair > {
static std::pair get(const foo& some_foo) {
    T1 t1 = ...;
    T2 t2 = ...;
    return std::make_pair(t1, t2);
};

and then call it like

getter >::get(some_foo);

though. You may have to do some messing around with friendship or visibility if get really needed to be a member function.

To elaborate on sbi's suggestion:

class foo {
   ...
   template
   T get() const;
};

template
T foo::get() const
{
  return getter::get(*this);
  /*            ^-- specialization happens here */
}

And now you're back to being able to say

std::pair p = some_foo.get >();