*(a++) is giving error but not *(a+1)?? where a is array name?

Question

In following code:

void main()
{
    char a[]={1,5,3,4,5,6};
    printf(\"%d\\n\",*(a++)); //line gives error: wrong type argument to increment
    printf(\"         


        

Answer 1

'a' behaves like a const pointer. 'a' cannot change it's value or the address it is pointing to. This is because compiler has statically allocated memory of size of array and you are changing the address that it is referencing to.

You can do it as follows instead

void main()
{
char a[]={1,5,3,4,5,6};
char *ch;
ch=a;
printf("%d\n",*(ch++)); //this lines gives error no more
printf("%d\n",*(ch+1));
}