*(a++) is giving error but not *(a+1)?? where a is array name?

Question

In following code:

void main()
{
    char a[]={1,5,3,4,5,6};
    printf(\"%d\\n\",*(a++)); //line gives error: wrong type argument to increment
    printf(\"         


        

Answer 1

Okay seriously bad coding practices: However let's first address your issue:

printf("%d\n",*(a++)); //this lines gives error: wrong type argument to increment

can't be used because a is an implicit reference to the array;

You CAN do this:

char b[]={1,5,3,4,5,6};
char *a = b;
printf("%d\n",*(a++)); //this lines will not give errors any more

and off you go...

Also *(a++) is NOT the same as *(a+1) because ++ attempts to modify operand whereas + simply add one to constant a value.