C++11 Lambda functions implicit conversion to bool vs. std::function

Question

Consider this simple example code:

#include 
#include 

void f(bool _switch) {
    std::cout << \"Nothing really\" &l         


        

Answer 1

You can get rid of the implicit conversion by creating a helper class

#include 
#include 

struct Boolean { 
    bool state; 
    Boolean(bool b):state(b){} 
    operator bool(){ return state; } 
};
void f(Boolean _switch) {
    std::cout << "Nothing really " << _switch << std::endl;
}

void f(std::function _f) {
    std::cout << "Nothing really, too" << std::endl;
}

int main ( int argc, char* argv[] ) {
    f([](int _idx){ return 7.9;});
    f(true);
    return 0;
}

Should you ever want to call f with eg. a pointer and expect it to call the first overload you will have to cast it to either bool or add a corresponding constructor / cast to the helper class though.