Safari is not respecting scaling applied to a foreignObject

Question

The following is a strange, and clearly buggy behavior of Safari (tested with versions 11 & 12). A containing HTML, when scaled, still

Answer 1

I couldn't think of any decent solution either, so I came up with a little hacky approach - you need to place the svg into the container, then get the width of the container and width of the svg, scale accordingly and position it properly:

if (window['safari'] !== undefined) {
    const svgContainerElement = document.getElementById('svgContainer');
    const svgElement = document.getElementById('svg');

    const zoomLevel = svgContainerElement.clientWidth / 867; // width of the foreign object
    svgElement.style.transform = `scale(${zoomLevel})`;

    const leftOffset = svgContainerElement.getBoundingClientRect().left - 
    svgElement.getBoundingClientRect().left;
    const topOffset = svgContainerElement.getBoundingClientRect().top - 
svgElement.getBoundingClientRect().top;

    svgElement.style.position = `relative`;
    svgElement.style.left = leftOffset;
    svgElement.style.top = topOffset;
}

you may be forced to re-draw the svg if the browser doesn't react to the style changes properly:

const parent = svgElement.parentElement;
if (parent) {
    parent.removeChild(el);
    parent.appendChild(el);
}

It may be like a few years late to this question, but I hope it will help somebody since this is a problem in safari to this date (November 2019)