If you take Java\'s primitive numeric types, plus boolean, and compare it to C++ equivalent types, is there any difference what concerns the operators, like precedence rules
See this:
int a = 0; int b = (a++) + (a);
int a = 0;
int b = (a++) + (a);
If you print b then it will output 0 in C++ whereas 1 in Java
b
0
1