Function returning boolean fails on “expression is of wrong type”

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离开以前 2021-01-11 10:35

I am using oracle 11g and I just cant under stand where my problem is. I have made much more difficult stuff but I fail in this simple thing for the last 5 hr :

Thi

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  •  攒了一身酷
    2021-01-11 11:10

    Given that you are calling this within SQL, you could use the built-in SIGN function instead of rolling your own.

    The function will return -1, 0 or 1, depending on the sign of the parameter (negative, zero or positive respectively).

    Here's how you would use it:

    SIGN(level_existance*types_with_impel)
    

    And how you would work it into a CASE statement:

    SELECT CASE WHEN (SIGN(level_existance*types_with_impel) = 1)
                THEN 'TRUE'
                ELSE 'FALSE'
           END legal_user
    FROM ...
    

    In this case, I'm just returning a string ('TRUE' or 'FALSE'), but you can return anything that's valid within your SELECT statement (a column, SYSDATE, etc).

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