Calling an overridden method, superclass an calls overridden method

Question

This code throws an exception, AttributeError, \"wtf!\", because A.foo() is calling B.foo1(), shouldn\'t it call A.foo1()? Ho

Answer 1

In the code:

def foo2(self):
    super(B, self).foo()

self is an instance of B.

When a method derived from A is called by an instance of B it will start looking in the namespace from B, and only if the method is not found (e.g. is not overridden by B) the implementation from A is used, but always with self referring to B. At no point self is an instance of A.