More efficient choice comparison for Rock Paper Scissors

Question

This is an ongoing school project that I would like to improve. The point is to make the code as efficient (or short) as possible. I would like to reduce it by finding an al

Answer 1

Switch statements goes like that. Try to look at the e.g i gave you and try to understand the flow of the code.

Best way to learn is with your hands! Random switch eg:

   switch(expression) {
   case x:
    code block
    break; // after every statement e.g: (console.log) you need to use 
   "break"
    case y:
    code block
    break;
    default:
    code block

}

Your code:

switch (weapon) {
 case chosenOne:
    return console.log(alert("It's a tie! Try again to win!"));
    break;
 case "Rock":
 case "Paper":
 alert("You lost! Paper beats the rock.");
   break;
  case "Paper":
 case "Scissors":    
  console.log(alert("You lost! The scissors cut the paper."))
   break;
  case "Scissors":
 case "Rock": 
console.log(alert("You lost! The rock beats the scissors."))
break;
case "Scissors":
   case "Paper" :
    alert("You won! Scissors cut the paper.");
  break;
case "Paper":
case "Rock":
    console.log(alert("You won! Paper beats the rock."))
   break;
  case "Rock": 
  case "Scissors": 
        alert("You won! The rock beats the scissors.");
    default:
   return "somthing went wrong"
      break;