creating a new list with subset of list using index in python

Question

A list:

a = [\'a\', \'b\', \'c\', 3, 4, \'d\', 6, 7, 8]

I want a list using a subset of a using a[0:2],a[4], a[6:],

t

Answer 1

Suppose

a = ['a', 'b', 'c', 3, 4, 'd', 6, 7, 8]

and the list of indexes is stored in

b= [0, 1, 2, 4, 6, 7, 8]

then a simple one-line solution will be

c = [a[i] for i in b]