C sizeof char pointer

Question

Why is size of this char variable equal 1?

int main(){

char s1[] = \"hello\";

fprintf(stderr, \"(*s1) : %i\\n\", sizeof(*s1) )    // prints out 1

}
         


        

Answer 1

Why is size of this char variable equal 1?

Because size of a char is guaranteed to be 1 byte by the C standard.

*s1 == *(s1+0) == s1[0] == char

If you want to get size of a character pointer, you need to pass a character pointer to sizeof:

sizeof(&s1[0]);