C sizeof char pointer

Question

Why is size of this char variable equal 1?

int main(){

char s1[] = \"hello\";

fprintf(stderr, \"(*s1) : %i\\n\", sizeof(*s1) )    // prints out 1

}
         


        

Answer 1

NOTA: the original question has changed a little bit at first it was: why is the size of this char pointer 1

sizeof(*s1)

is the same as

sizeof(s1[0]) which is the size of a char object and not the size of a char pointer.

The size of an object of type char is always 1 in C.

To get the size of the char pointer use this expression: sizeof (&s1[0])