I have a dataset with 6 elements.
An I would like to draw a venn diagram, but with R (Venndiagram library) it\'s limited at 5 elements.
Do you know how can
Thanks @ben-frederickson for both the answer and your fine venn.js library. If the user would like to solve the problem in R
with the new d3vennR
htmlwidget, here is my answer. It is not the most efficient method, but it works.
# devtools::install_github("timelyportfolio/d3vennR")
library(d3vennR)
library(sets)
sets_df <- read.csv(
textConnection("Ath,Fve,Mdm,Pcmm,Pper,Pmum,Counts
1,0,0,0,0,0,901
0,1,0,0,0,0,14764
0,0,1,0,0,0,19408
0,0,0,1,0,0,17714
0,0,0,0,1,0,16849
0,0,0,0,0,1,17572
1,1,0,0,0,0,823
1,0,1,0,0,0,846"
)
)
# get all sets provided and their counts/size
sets_list <- apply(
sets_df
,MARGIN=1
,function(rw){
list(
sets = as.list(colnames(sets_df)[which(rw==1)])
, size = as.numeric(tail(rw,1))
)
}
)
# get all set combinations to fill with size = 0 where missing
sets_combinations <- lapply(
# answer by venn.js authors only goes to combinations of m=2
# this goes to combinations of m = sets - 1
seq.int(1,length(colnames(sets_df))-2)
,function(m){
t(combn(colnames(sets_df)[-length(colnames(sets_df))],m=m))
}
)
# now combine the sets and sizes provided in data with the sets and 0
sets_venn <- unlist(
lapply(
sets_combinations
,function(x){
apply(
x
,MARGIN=1
,function(y){
# this gets sets of 0 which are not in the data provided
if(!set_contains_element(
as.set(lapply(sets_list,function(z){as.set(unlist(z$sets))}))
,as.set(y)
)){
list(sets=y,size=0)
} else {
# this gets sets with their sizes given by the partial data provided
unlist(
Filter(
function(z){
set_is_equal(as.set(y),as.set(unlist(z$sets)))
}
,sets_list
)
,recursive=F
)
}
}
)
}
)
,recursive=F
)
# produce the Venn Diagram in R with the transformed data
d3vennR( data = sets_venn )